A cannon is fired with an initial horizontal velocity of 20 m/s and initial vertical velocity of 25 m/s. After 3s in the air, the canon hits its target. How far away was the canon from its Target?

140.16m

Explanation:

To get the distance the cannon is away from its target, we will apply the equation of motion;

S = ut + 1/2gt²

u is the resultant initial velocity

g is the acceleration due to gravity

t is the time taken.

Given

g = 9.8m/s²

t = 3s

u = √20²+25²

u = √400+625

u = √1025

u = 32.02m/s

Substitute the values into the formula and get the distance S;

S = 32.02(3)+ 1/2(9.8)3²

S = 96.06+44.1

S = 140.16m

Hence the cannon was 140.16m away from its target

the displacement produced by the body.  

the amount of force subjected to the body.  

the angle between the direction of force and displacement

electromagnetic shielding is the practice of reducing the electromagnetic field in a space by blocking the field with barriers made of conductive or magnetic materials. shielding is typically applied to enclosures to isolate electrical devices from their surroundings, and to cables to isolate wires from the environment through which the cable runs. electromagnetic shielding that blocks radio frequency electromagnetic radiation is also known as rf shielding.

the shielding can reduce the coupling of radio waves, electromagnetic fields and electrostatic fields. a conductive enclosure used to block electrostatic fields is also known as a faraday cage. the amount of reduction depends very much upon the material used, its thickness, the size of the shielded volume and the frequency of the fields of interest and the size, shape and orientation of apertures in a shield to an incident electromagnetic

from wikipedia