A dog chases a skateboarder travelling at 10.4m/s. The skateboarder speeds up with a constant acceleration for 39m over 3.3s. We want to find the acceleration of the skateboarder over the 3.3s time interval.

The acceleration of the skateboarder over the 3.3s time interval is 3.15 m/s²

Explanation:

Acceleration can be described as the rate of change of velocity (as seen in the question). The formula to be used here to determine the acceleration is

Acceleration (in m/s²) = velocity (m/s) ÷ time (s)

Acceleration = 10.4 ÷ 3.3

Acceleration = 3.15 m/s²

Thus, the acceleration of the skateboarder over the 3.3s time interval is 3.15 m/s²

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2