Physics please help me.

F = 780 [N]

Explanation:

To solve this problem we must use newton's second law which tells us that the sum of forces on a body must be equal to the product of mass by acceleration

ΣF =m*a

where:

F = force [N] (units of Newtons)

m = mass = 2600 [kg]

a = acceleration = 0.3 [m/s²]

F = 2600*0.3

F = 780 [N]

two charges are fixed in place on the x-axis as shown. the charge at x = 0 is negative and has magnitude q = 2 μcoulombs (1 μcoulomb = 10-6 coulombs). the charge at x = d, (d = +12 cm), is positive and has magnitude q = 4 μcoulombs. find a point x = xo along the x-axis at which the electric field is zero.