You throw a baseball from the roof of a house to a friend on the ground. The ball has an initial velocity of 12.0 m/s in the horizontal direction. After 1.00 s, how fast is the ball
moving in (a) the x direction and (b) the y direction. A) the velocity in the x-direction
doesn't change. Therefore, after 1.00 seconds we have
Please help!!

(a) The final velocity of the ball after 1,0 second in y - direction is -9.8 m/s.

(b) The final velocity of the ball after 1,0 second in x - direction is 12 m/s.

The given parameters:

The final velocity of the ball after 1,0 second in y - direction is calculated as follows;

The final velocity of the ball after 1,0 second in x - direction is calculated as follows;

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a) 12.0 m/s

b) 9.81 m/s in the downward direction

Explanation:

The initial velocity of the ball in the horizontal direction = 12.0 m/s

a) The velocity of the baseball in the x-direction remains the same therefore, we have;

The velocity of the ball in the x-direction (horizontal direction) after 1 second = 12.0 m/s because there is no net acceleration in the horizontal direction

b) The velocity in the y-direction is given by the following kinematic equation;

v = u - g × t

Where;

v = The final vertical velocity of the ball after t seconds

u = The initial vertical velocity = 0

g = The acceleration due to gravity = 9.81 m/s²

t = The time taken in motion = 1.00 s

Substituting the values gives;

v = 0 - 9.81 m/s² × 1.00 s = -9.81 m/s

v = -9.81 m/s

The vertical velocity of the ball after 1.00 second = -9.81 m/s which is 9.81 m/s downwards.

what are the options.

explanation:

1.195000

explanation:

total mass=0.0117+0.0137+0.0881+0.0111

total mass= 0.01172kg

total velocity = 0.283-0.743+0.871-0.799+0.155+0.637+0.301=0.102

momentum=mv=0.1172*0.102=1.195000//