A Cessna aircraft has a lift off speed of 147 km/h. What minimum constant acceleration does this require if the aircraft is to be airborne after a take off run of 208 m?

The acceleration is  

Explanation:

From the question we are told that

   The lift up speed is  

    The distance covered for the take off run is

Generally from kinematic equation we have that

Here u is the initial  speed of the aircraft with value 0 m/ s give that the aircraft started from rest

So  

=>  

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.

it is a negative acceleration