A force of 6.00 N acts in the positive direction on a 3.00 kg object, originally traveling at +15.0 m/s, for 10.0 s. (a) What is the object's change in momentum?

60 kg m/s

Explanation:

Let be the acceleration of the object.

As the acceleration of the object is constant, so

Given that applied force, F=6.00 N,

From Newton's second law, we have

,

[from equation (i)]

[given that time, t=10 s and F=6 N]

Here mv is the final momentum of the object and mu is the initial momentum of the object.

So, the change in the momentum of the object is mv-mu.

Hence, the change in the momentum of the object is 60 kg m/s.