If a single circular loop of wire carries a current of 63 A and produces a magnetic field at its center with a magnitude of 1.70 10-4 T, determine the radius of the loop.

The radius of the circular loop is 0.233 m

Explanation:

Given;

current on the circular loop, I = 63 A

magnitude of the magnetic field, B = 1.7 x 10⁻⁴ T

The magnetic field at the center of a circular loop is given by;

Where;

R is the radius of the circular loop

μ is the permeability of free space = 4π x 10⁻⁷ T.m/A

Substitute the givens;

Therefore, the radius of the circular loop is 0.233 m

365.25 earth days are in the year of a light year

96.77 amp

explanation:

rl = 250/100 = 2.5 ohms.

egl = 250 + (100 × 0.1) + 2 = 262 v.

at 700 r.p.m., eg2 = 262 × 700/1000 = 183.4 v.

if ia is the new current, then eg2 - 2 - (ia × 0.1) = 2.5 ia

which means this will give ia = 96.77 amp.