A ball is thrown up into the air with the initial velocity of 18 m/s. A) How high does the ball go? B) Calculate the time needed for the ball to reach its max height.

(a) h = 16.53 m (b) t = 1.83 s

Explanation:

Given that,

The initial velocity of a ball, u = 18 m/s

When it reaches to the maximum height, its final velocity v will be 0. Let it goes to a maximum height of h meters.

Finding t using first equation of motion as follows :

v = u +at

Here, a = -g and v = 0

The time needed for the ball to reach its max height is 1.83 s.

Let h is the maximum height. Using second equation of motion to find it :

So, it will go to a maximum height of 16.53 m.

the focus of lesson 1 is newton's first law of motion - sometimes referred to as the law of inertia. newton's first law of motion is often stated as. an object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.

explanation: