A baseball is thrown at an angle of 25 degrees relative to the ground at a speed of 23 m/s. If the ball was caught 42 m from the thrower: What is the initial vertical velocity?

What is the initial horizontal velocity?

How long was it in the air?

How high did the ball travel before being caught?

a)

b)

c)

d)

Explanation:

a) The initial vertical velocity is given by:

Where:

θ: 25°

v: is the magnitude of the speed = 23 m/s

b) The initial horizontal velocity can be calculated as follows:

c) The flight time can be calculated using the following equation:

Where:

x: is the total distance = 42 m

d) The maximum height is given by:

Where:

: is the final vertical velocity =0 (at the maximum heigth)

g: is the gravity = 9.81 m/s²

I hope it helps you!                                  

f=ma a/f/m a= 480/60 a = 8m/s/s that is quick wow

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