A space probe lands on a newly discovered planet. A small canister is released from the probe and falls a distance of 3 m in 0.5 sec. What is the value for the acceleration of gravity on this new planet?

24m/s²

Explanation:

Given

Distance S = 3m

Time of fall = 0.5sec

Required

Acceleration due to gravity

Using the equation of motion

S = ut+1/2gt²

Substitute the given values

3 = 0+1/2g(0.5)²

3 = 1/2(0.25)g

3 = 0.125g

g = 3/0.125

g = 24

Hence the value for the acceleration of gravity on this new planet is 24m/s²

answer; ///i believe that the correct answer is (45*) at a 45 degree check first good