A player kicks a football from ground level with a velocity of magnitude 27.0 m/s at an angle of 30° above the horizontal.
What is the horizontal distance the ball travels?
(hint: d= 1/2 at^2)

37.33m

Explanation:

To calculate the distance using d= 1/2 at², the time taken for this projectile object (ball) must be calculated.

Time of a projectile = 2u sinθ/ g

Where u = velocity = 27m/s

g = 9.8m/s²

θ = 30°

T = 2usinθ/ g

T = 2 × 27 × sin 30°/9.8

T = 54sin30°/9.8

T = 27/9.8

T = 2.755

T = 2.76s

If the time taken for the ball to move is 2.76s, the distance travelled is:

D = 1/2at²

D = 1/2 × 9.8 × 2.76²

D = 1/2 × 9.8 × 7.6176

D = 74.65248/2

D = 37.33m

The horizontal distance the ball travels is 37.33m

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