A roller coaster accelerates from an initial speed of 6.0 m/s to a final of 70 m/s over 4 seconds. What is the rigth formula to solve the problem? Acceleration formulas: 1) v2=v1+ at 2)d=1/2(v2-v1)t 3)d=v1t + 1/2 at2 4) d=v2t - 1/2 at2 5) v2=v1+2ad a 1 b 2 c 3 d 4 e 5

a = 16 m/s²

Explanation:

Given that,

Initial speed of a roler coaster, v₁ = 6 m/s

Final speed of a roller coaster, v₂ = 70 m/s

Time, t = 4s

We know that, acceleration of an object is equal to the rate of change of velocity. Let the acceleration be a. Its formula is given by :

or

The correct option is (1). Its value is equal to :

Its value is equal to 16 m/s².

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j

the tires are rotating at 0.434 rpmlinear speed=45 m/sdiameter=0.550 mradius=0.275 mnow v= rωω= v/rω=45/0.275ω=163.6 rad/sω=163.6 rad/s (1rev/2π rad) (60s/1m)ω=1563 rpm