A hot piece of brass (c = 380 J/kg˚C) is placed in water (c = 4180 J/kg˚C) to cool. The final temperature of the “mixture” will be closer to the initial temperature of which substance? Explain.

Given :

A hot piece of brass (c = 380 J/kg˚C) is placed in water (c = 4180 J/kg˚C) to cool.

To Find :

The final temperature of the “mixture” will be closer to the initial temperature of which substance.

Solution :

We know, change in temperature is inversely proportional to specific heat of the material.

In the given case specific heat of water is much greater than specific heat of brass.

So, change in temperature will be much in brass as compared to water.

Therefore, final temperature of mixture will be closer to the initial temperature of water.

Hence, this is the required solution.

15.3 cos 65 degrees trig

beta is electron from nucleus

something from nucleus has changed, but charge must be same for cons of charge