A worker has to move a 800 kg crate. He pulls with a force of 5,700 N and the Force of Friction working against him is 900 N. What is the acceleration
of the crate?

we have that from the Question, it can be said that  the acceleration  of the crate is

a=6m/s^2

From the Question we are told

A worker has to move a 800 kg crate. He pulls with a force of 5,700 N and the Force of Friction working against him is 900 N.

What is the acceleration  of the crate?

Generally the equation for acceleration is mathematically given as

a=6m/s^2

Therefore

the acceleration  of the crate is

a=6m/s^2

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There is a net force being applied in the direction that the crate is being pulled of 5700 N - 900 N = 4800 N.

By Newton's second law, this net force is proportional to the crate's acceleration a by a factor of the crate's mass:

4800 N = (800 kg) a

a = (4800 N) / (800 kg)

a = 6 m/s²

we need answer choices

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day