The pressure at the pump outlet is 2372 psi. If the pump has a mechanical efficiency of 0.93, what input horsepower is required to drive the pump

HP = 27.08 hp

Explanation:

The complete question has a theoretical flow rate of 18.2 GPM. So, to find the input horsepower, we will use the following formula:

HP = QP/1714(E)

where,

HP = Input Horse Power = ?

Q = Volume Flow Rate in Gallons Per Minute (GPM) = 18.2 GPM

P = Outlet Pressure in psi = 2372 psi

E = Mechanical Efficiency = 0.93

Therefore,

HP = (18.2 GPM)(2372 psi)/(1714)(0.93)

HP = 27.08 hp

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