Find E⃗ E→E_vec, the electric field inside the cube. Express the electric field in terms of v0v0v_0, B0B0B_0, and unit vectors ( i^i^i_unit, j^j^j_unit, and/or k^k^k_unit).

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electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j

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