A 500-kg sack of coal is dropped on a 2000-kg railroad flatcar which was initially moving at 3 m/s. After the sack rests on the flatcar, the speed of the flatcar is:

heat the gas and measure the pressure

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer

r = ρ x length / area  

ρ = r x area / length  

ρ is in ohm-meters  

in basic units, it is m³kg/s³a²  

i think this is it.