A stone is released from rest from a height of 60 m. How long does it take to hit the ground? 4.4 s
2.3 s
5.2 s
3.5 s

It would take a stone released from a height of 60m, 3.5s to hit the ground.

EQUATION OF MOTION:

Where;

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3.5 s

Explanation:

Given

--- because it starts from rest

Required

Determine time (t) to hit the ground

This can be solved using the following motion equation

Substitute values for S and u and take g as 9.8m/s^2

Multiply through by 2

Solve for t^2

Take square roots

---- approximated

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.