Calculate the net acceleration acting on a 40 kg box being pushed across a horizontal floor. There is a 400 N normal force, a 195 N applied force, and a 55 N force of friction resisting any sliding motion. Assume g = 10 m/s ^ 2

Net acceleration = 3.5m/s²

Explanation:

Given the following data;

Mass, m = 40kg

Normal force, Fn = 400N

Applied force, Fapp = 195N

Force of friction, Ff = 55N

Mathematically, the net force is given by the formula;

Substituting into the equation, we have;

To find the acceleration;

Making acceleration "a" the subject of formula;

Net acceleration, a = 3.5m/s²

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz