A 4500 kg car is pushed by 3 boys who exert a force totaling 1500 N. When the boys begin to push the car it is traveling 4.5 m/s. What is the velocity of the car after 3.0 seconds?

The velocity of the car after 3 seconds is 5.5 m/s

Explanation:

Mathematically, we can get the acceleration of the car first;

F = m•a

where m is the mass, F is the applied force and a is the acceleration

from the question;

F = 1500 N , m = 4500 kg and a = ?

By rewriting the formula;

a = F/m

a = 1500/4500 = 1/3 m/s^2

Now to get the velocity of the car after 3 seconds;

Mathematically;

V = U + at

where V is the final

velocity, U is the initial velocity,

From the question, we are trying to get V;

where U = 4.5 m/s

a = 1/3 m/s^2 and t = 3 seconds

Thus;

V = 4.5 + (1/3)(3)

V = 4.5 + 1

V = 5.5 m/s

force tends to be low and long diustance masses are high