A set of keys is tossed horizontally with speed 3.8 m/s from a lifeguard bench to 5.0 m above the ground. How far did they keys move out away from the bench horizontally before they hit the ground?

3.84 m

Explanation:

Height given h = 5 m .

time taken to fall vertically by 5 m will be equal to move horizontally before touching the ground . Let the time taken be t .

h = ut + 1/ g t²

5 = 1/2 x 9.8 x t²

t = 1.01 s

displacement in horizontal direction = velocity x time

= 3.8 x 1.01

= 3.84 m

need to see circuit to get time constant

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.