A moving electron accelerates at 5200 m/s^2 in a 55 degree direction. After 0.530 seconds, it has a velocity of 6598 m/s in a -20.5 degree direction. What is the y-component of the initial velocity?

-4568.25 m /s

Explanation:

Consider all velocity in y direction .

Acceleration in y direction = 5200 sin55 = 4259.59 m /s²

y component of final velocity = - 6598 sin 20.5 = - 2310.67 m /s

Let y component of initial velocity be u

v = u + at

- 2310.67 = u + 4259.59  x .53

- 2310.67 = u + 2257.58

u = - 4568.25 m /s

So y component of initial velocity

= -4568.25 m /s

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases . this process does not change the mass number.

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as -decay. in this the mass number remains same.

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

lol

explanation: