A resting object starts accelerating down a straight track. It accelerates at 2 m/s squared for 6.5 seconds, then and 8 m/s squared for 9.25 seconds, and finally at 4 m/s squared for 4.75 seconds. What is the objects final velocity

106 m /s

Explanation:

v = u + at

v is final , u is initial , a is acceleration and t is time .

velocity after initial 6.5 s

v = 0 + 2 x 6.5 = 13 m /s

This becomes initial velocity for 9.25 s stretch .

velocity after next 9.5 s

v = 13+ 8 x 9.25

= 87 m /s

This becomes initial velocity for 4.75 s stretch .

Final velocity after next 4.75 s

v = 87 + 4 x 4.75

= 106 m /s

the answer is b ) square root of 5

ok

explanation: