A 200 g block attached to a horizontal spring is oscillating with an amplitude of 2.0 cm and a frequency of 2.0 Hz. Just as it passes through the equilibrium point, moving to the right, a sharp blow directed to the left exerts a 20 N force for 1.0 ms. What are the new (a) frequency and (b) amplitude

a

The new frequency is  2.0 Hz

b

The new amplitude is

Explanation:

From the question we are told that

    The mass of the block is  

     The first  amplitude is  

      The frequency is

      The force exerted is  F = 20 N

      The duration of the force is  

Generally the impulse is mathematically represented as

=>      

=>      

Generally the initial angular speed of the block is mathematically represented as

=>    

=>    

Generally the  linear velocity of the block at the equilibrium position before the impact  is mathematically represented as

=>    

=>  

Generally the change in velocity after that impact of the force is mathematically represented as

=>    

=>    

Generally the  linear velocity of the block at the equilibrium position after the impact  is mathematically represented as  

=>    

=>    

This can also be mathematically represented as

=>  

=>

Generally given that the angular velocity does not change , it then implies that the frequency remains 2.0 Hz

c, 1a hope this

it doesn't. it was imagined up in the middle ages.