Two very long solenoids have the same length, but solenoid A has 18 times the number of turns, 1/5 the radius, and 7 times the current of solenoid B. Calculate the ratio of the magnetic field inside of A to that inside B.

Explanation:

Let n and n' be the number of turns in solenoid A and B. r and r' be the radius of solenoid A and B. I and I' be current in solenoid A and B.

ATQ,

n = 18 n'

r = (1/5)r'

I=7I'

The magnetic field inside the solenoid is given by :

So,

B and B' is the magnetic field in solenoid A and B.

So, the magnetic field inside the solenoid A is 126 times the magnetc field inside the solenoid B.

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