4. How much energy must be absorbed by water with a mass of 0.5 kg in order to raise the temperature from 30°C to 65°C? Note: Water has a specific heat of 4.190 J kg °C.

Q = 73325 J or 73.325 KJ

Explanation:

Given the following data;

Specific heat capacity of water = 4190

Mass = 0.5kg

dt = 65 - 30 = 35°C

Heat capacity is given by the formula;

Q = mcdt

Where,

Q represents the heat capacity.

m represents the mass of an object.

c represents the specific heat capacity of water.

dt represents the change in temperature.

Substituting into the equation, we have:

Q = 0.5 * 4190 * 35

Q = 73325 Joules.

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get the total number of pieces of fruit and divide it by 4 to get the average. the result is the answer to the problem. 14 total number of fruits and there are 4 members. 14 divided by 4 is equals to 3.5.