20 points - Brainliest A rock is thrown horizontally from a cliff at 40 m/s. If the rock lands 155 meters from the base of the cliff. How long was the rock in the air?

The known values are: \text{t}=2.35\:\text{s};\:\text{y}=0\:\text{m};\:\text{v}_0=+8.00\:\text{m/s};\:\text{a}=-9.8\:\text{m/s}^2

Based from the given values, we can use the equation y=y_0+v_0t+\frac{1}{2}at^2. Substituting the values, we have

0\:=\text{y}_0+\left(8.00\:\text{m/s}\right)\left(2.35\:\text{s}\right)+\frac{1}{2}\left(-9.80\:\text{m/s}^2\right)\left(2.35\:\text{s}\right)^2

y=8.26\:m

Therefore, the cliff is 8.26 meters high.

Explanation:

r=rho l/a where a is the area, l is the length and rho is resistivity so the greater the area the lesser the resistance thats why the earth pin is thicker bcos current follow the shortest path, so less resistive .

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