How much voltage is present in a circuit that carries 0.012 A with a resistance of 300 Ω?

3.6V

Explanation:

Given parameters:

Current  = 0.012A

Resistance  = 300Ω

Unknown:

Voltage  = ?

Solution:

According to ohm's law, voltage in a circuit is expressed mathematically as shown below:

   Voltage = Current x Resistance

 Insert the given parameters and solve;

 Voltage  = 0.012 x 300 = 3.6V

distance = 150m

displ = root (50 ^2 + 100^2)

root(2500+10000)

root 125000