4) The power supplies in 1206 Mudd feature an internal protection mechanism that limits the output current to 1 ampere (oh no, not that again). Ideally, the protection circuit engages instantaneously when an over-current fault is detected, then disengages instantaneously once the fault condition is removed. While in the current limited state, the supply acts like an ideal current source. Now suppose you set the supply to 5 volts then connect a 1H inductor (huge!) to it.(a) how long will it take for the supply to go into current-limit

0.2 seconds

Explanation:

Given data  :

Output Data = 1 ampere

supply voltage = 5 volts

inductor = 1 H

A) calculate how long before the supply goes into current limit

we apply this relationship used for determining output voltage

V = ------- ( 1 )

L = 1 H

di = 1 ampere

dt = ?

V = 5 volts

considering equation 1 above

dt ( time before supply goes into current limit ) =  1 / 5 = 0.2 seconds

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.