A 45 kg gymnast performing a giant swing with an angular velocity of 360 deg/sec exerts 60 Nm of torque on the support bar. It takes 0.5 sec to complete one full swing (360 deg). How much torque does the bar on the gymnasts hands exert

the  amount of torque the bar on the gymnast's hands  is 60 Nm

Explanation:

Given that:

The mass of the gymnast = 45 kg

The angular velocity = 360 deg/sec

The torque = 60 Nm

Time taken to complete 1 revolution = 0.5 sec

Newton's Third Law of motion posits that there is always an equal reaction in every reaction but in the opposite direction.

Now, the amount of torque the bar on the gymnast's hands exerts is equal to the torque on the support bar.

Therefore, the  amount of torque the bar on the gymnast's hands  is 60 Nm

hey , the answer is c

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.