A box of mass 30 kg requires 34N to slide across a surface. What is tbe weight of the box? What is the coefficient of friction between the box and surface? show work

Weight of the box= 300 Newtons, Coefficient of Friction=.113

Explanation:

The weight of the box can be calculated with mass*g (I'll be using g=10m/s^2). This results in a weight of 300 Newtons. Assuming that the box is sliding with zero acceleration (constant velocity), the net force on the box equals zero. Since the person is pushing on the box with 34 newtons, the force of kinetic friction must equal 34 newtons to get a net force of zero. Using the equation 34=uMg(uMg is the formula for the force of friction) solve for u to get the coefficient of kinetic friction.

nah.   i'm just sleepy.