"The magnitude of the acceleration due to gravity on the surface of planet A is twice as great as on the surface of planet B. What is the ratio of the weight of mass X on the surface of planet A to its weight on the surface of planet B?"

2 : 1

Explanation:

Given that The magnitude of the acceleration due to gravity on the surface of planet A is twice as great as on the surface of planet B. What is the ratio of the weight of mass X on the surface of planet A to its weight on the surface of planet B?"

Since the magnitude of the acceleration due to gravity on the surface of planet A is twice as great as on the surface of planet B. And

Weight W = mg

Mass is always constant

2g : g

The ratio of the weight of mass X on the surface of planet A to its weight on the surface of planet B will be:

2 : 1

r=rho l/a where a is the area, l is the length and rho is resistivity so the greater the area the lesser the resistance thats why the earth pin is thicker bcos current follow the shortest path, so less resistive .

b would be the answer