)A ball is hit straight up with an initial speed of 50 meters per second. What is the speed of the ball 3 seconds after it is hit? [Neglect friction.]

The velocity of the ball after 3 seconds it is hit, is 20.6 m/s

Explanation:

Given;

initial velocity of the ball, u = 50 m/s

time of the upward motion of the ball, t = 3 seconds

The velocity of the ball after 3 seconds is calculated by applying the following kinematic equation;

v = u - gt

where;

g is acceleration due to gravity = 9.8 m/s²

v = 50 - (9.8 x 3)

v = 50 - 29.4

v = 20.6 m/s

Therefore, the velocity of the ball after 3 seconds it is hit, is 20.6 m/s

answer; /// the above statement is (true);