A projectile is launched at an angle of 45 degrees with a velocity of 250 m/s. If air resistance is neglected, the magnitude of the horizontal velocity of the projectile at the time it reaches maximum altitude is equal to

The horizontal velocity of the projectile at the time it reaches maximum altitude approximately equal to 131.331 meters per second.

Explanation:

From Mechanical Physics we understand that projectile motion is the combination of a horizontal motion at constant velocity and a vertical uniform accelerated motion due to gravity. Then, the horizontal velocity of the projectile (), measured in meters per second,  remains constant during motion. That is:

(Eq. 1)

Where:

- Initial velocity of the projectile, measured in meters per second.

- Launch angle above the horizontal, measured in sexagesimal degrees.

If we know that and , then horizontal velocity of the projectile at the time it reaches maximum altitude is:

The horizontal velocity of the projectile at the time it reaches maximum altitude approximately equal to 131.331 meters per second.