A 0.6 kg basketball moving 7.2 m/s to the right collides with a 0.04 kg tennis ball moving 22 m/ s to the left. After the collision, the tennis ball is moving 32.7 m/s to the right. What is the velocity of the basketball after the collision?

Explanation:

Given data

mass of basket ball m1=0.6kg

mass of tennis ball m2= 0.04kg

velocity of basket ball v1=7.2m/s

velocity of  tennis ball  v2=22m/s

velocity of basket ball v3=?

velocity of  tennis ball  v4=32.7m/s

we know that the expression for elastic collision is given as

m1v1+m2v2=m1v3+m2v4

substituting we have

0.6*7.2+0.04*22=0.6*x+0.04*32.7

4.32+0.88=0.6x+1.308

solving for x we have

3.892=0.6x

divide both side be 0.6 we have

x=3.892/0.6

x=6.49m/s

The velocity of the basketball after the collision is 6.49m/s

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