A 250-kg motorcycle goes around an unbanked turn of radius 13.7 m at a steady 96.5 km/h. What is the magnitude of the net force on the motorcycle

Given:

As we know, the centripetal force is given by:

→

By substituting the values, we get

or,

Thus the solution above is correct.

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13,116.35N

Explanation:

Magnitude of the net force on the motorcycle is expressed as;

F = mv²/r

m is the mass of the motorcycle

v is speed = 96.5km/hr

r is the radius = 13.7m

Convert speed to m/s:

96.5km/hr = 96.5×1000/1×3600

Speed = 96500/3600

Speed = 26.81m/s

Get the magnitude of the force:

F = 250×26.81²/13.7

F = 179,694.025/13.7

F = 13,116.35N

Hence the magnitude of the net force on the motorcycle is 13,116.35N

what was the acceleration of the 2 kg cart?

⇒ 16.0 cm/s2

what was the acceleration of the 4 kg cart?

⇒ 8.1 cm/s2

what was the acceleration of the 6 kg cart?

⇒ 5.3 cm/s2