If a volleyball accelerates towards the ground at 10m/s/s and it takes 1.6 seconds to hit the ground, how tall is the building

Distance, S = 12.8m

Explanation:

Given the following data;

Acceleration = 10

Time = 1.6

Initial velocity = 0

To solve for acceleration, we would use the second equation of motion;

Substituting the values into the equation;

Distance, S = 12.8m

Therefore, the height of the building is 12.8 meters.

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