Starting at rest at the top of a ski slope, you travel down the hill reaching a velocity of 20 m/s after 13 seconds. Once you reach the bottom of the hill you travel at a constant velocity of 20 m/s for the next 7 seconds. Sketch a quantitative (with numbers) position vs time, velocity vs time, and acceleration vs time graph of the skier's motion. PLEASE SHOW WORK AND I WILL MARK YOU THE BRAINLIEST

The graphs are attached

Explanation:

We are told that he started at rest at rest and travelled down the hill reaching a velocity of 20 m/s after 13 seconds.

Acceleration is gotten from;

v = u + at

a = (v - u)/t

a = (20 - 0)/13

a = 20/13 m/s² or 1.54 m/s²

Distance in this period is gotten from;

v² = u² + 2as

s = (v² - u²)/2s

s = (20² - 0²)/(2 × 20/13)

s = 400/(40/13)

s = 130 m

We are told that after reaching the bottom of the hill, he travelled at a constant velocity of 20 m/s for the next 7 seconds.

At constant velocity, acceleration is 0.

Thus,distance in this period is;

s1 = vt = 20 × 7 = 140 m

I've attached the graphs

force tends to be low and long diustance masses are high