34. If R = 4.0 kΩ, C = 3.0 mF, ε = 15 V, Q = 12 mC, and I = 2.0 mA, what is the potential difference Vb − Va?

the potential difference Vb − Va = -3 V

Explanation:

The potential difference Vb − Va s given by

Vb − Va=  Capacitance / Charge + current x resistance - Electromotive force

Vb − Va=Q/C + I X R - E

V=Q / C=(12 x 10^-3) / (3 x 10^-3)

=0.012/0.003ss

=4V

alsoV=  1R = 2.0 x 10^-3 x 4 x 10^3

=0.002 X 4000

=8

Vb − Va= 4V + 8V- 15V

= -3V

Therefore, the potential difference Vb − Va = -3 V

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