A cyclist is riding a bike with an initial speed of 4 m/s and accelerates uniformly at 2 m second squared in the same direction of its motion along the street what is the speed of the cyclist after traveling 6 m ?

6.32m/s

Explanation:

Given parameters:

Initial velocity  = 4m/s

Acceleration  = 2m/s²

Distance covered  = 6m

Unknown:

Final velocity  = ?

Solution:

To solve this problem, we have to apply the appropriate motion equation;

         V²  = U² + 2aS

where V is final speed

          U is the initial speed

         a is the acceleration

          S is the distance

Insert the given parameters and solve;

      V² = 4² + 2 x 2 x 6

      V² = 16 + 24

      V² = 40

       V = √40 = 6.32m/s

show the wavelengths of a wave. show the crests of a wave.

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.