If the rock is kicked at initial velocity of 12 m/s from a height of 106 m above the ground what horizontal distance does the rock travel before striking the ground?

74 m.

Explanation:

From the question given above, the following data were obtained:

Height (h) = 186 m

Initial velocity (u) = 12 m/s

Horizontal distance (d) =?

Next, we shall determine the time taken for the rock to get to the ground. This can be obtained as follow:

Height (h) = 186 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

H = ½gt²

186 = ½ × 9.8 × t²

186 = 4.9 × t²

Divide both side by 4.9

t² = 186/4.9

Take the square root of both side

t = √(186/4.9)

t = 6.16 s

Thus, the time taken for the rock to get to the ground is 6.16 s

Finally, we shall determine the horizontal distance travelled by the rock as follow:

Initial velocity (u) = 12 m/s

Time (t) = 6.16 s

Horizontal distance (d) =?

Horizontal distance (d) = Initial velocity (u) × Time (t)

d = u × t

d = 12 × 6.16

d = 73.92 ≈ 74 m

Therefore, the horizontal distance travelled by the rock is 74 m

i think it’s a. this is because if they measured the mass of something with a mass of 150g, then their final answer would have to be approximately 150g. though all of their answers are almost 150, rosa and tran have the closest answers (or the exact answer) to the accurate one.

are you like autistic or something?

xd