What is the freezing point (in degrees Celcius) of 4.62 kg of water if it contains 236.5 g of C a B r 2

The new freezing point of water is -0.476°C.

Explanation:

Given that,

Mass of water = 4.62 kg

Mass of CaBr₂ = 236.5 g

We need to calculate the molality of solution

Using formula of molality

Put the value into the formula

We need to calculate the depression in freezing point of water

Using formula of freezing point

Where, k = depression constant

m = molality of solution

Put the value into the formula

We know that,

The standard freezing point of water is 0°C

We need to find the new freezing point of water

Using formula for freezing point of water

Freezing point of 4.62 kg of water = freezing point of water-depression in freezing point of water

Put the value into the formula

Hence, The new freezing point of water is -0.476°C.