A ball is shot horizontally at 17.3m/s from the roof of a building 55.2 m tall, (use g = 9.8 m/s ^ 2) How far from the base of the building does the ball land?

Given that,

The initial speed of a ball, u = 17.3 m/s

It is shot from the roof of a 52 m tall building, h = 52 m

It is required to find the distance from the base of the building the ball land. Let the distance be d.

Final velocity of the ball, v = 0 (when it lands)

We can use third equation of motion to find it.

a = -g

So, it will land at a distance of 15.26 m.

gravitational energy

electrical energy

kinetic energy

ligh energy