A ball is shot horizontally at 17.3m/s from the roof of a building 55.2 m tall, (use g = 9.8 m/s ^ 2) How far from the base of the building does the ball land?

Given that,

The initial speed of a ball, u = 17.3 m/s

It is shot from the roof of a 52 m tall building, h = 52 m

It is required to find the distance from the base of the building the ball land. Let the distance be d.

Final velocity of the ball, v = 0 (when it lands)

We can use third equation of motion to find it.

a = -g

So, it will land at a distance of 15.26 m.

answer: the direction of the wind is expressed as the direction from which the wind is blowing. for example, easterly winds blow from east to west, while westerly winds blow from west to east.

explanation: