2. A motorcycle starts at rest and moves a distance of 350 m. If it has a constant acceleration of 4.55m/s2, what is its final velocity?

Vf = ≈56.436 m/s

Explanation:

We'll need to use the equation:

Vf^2 = Vi^2 + 2aΔx

Plugging in what we know, we get:

Vf^2 = (0)^2 + 2(4.55)(350)

Finally, some algebra:

Vf^2 = 3185

Vf = ≈56.436

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees. 

f=ma newton's second law 7x8=56n