Acar accelerates uniformly in a straight line from rest at the rate of 2.3 m/s^2. what is the speed of the car after it has traveled 55m? how long does it take the car to travel 55m?

According to the 3rd motion equation
vf^2=vi^2+2ad
since it has moved from rest ..therefore vi=0
vf^2=2×2.3×55=253 m/s
so vf=sqr(253) m/s

to get tge time...according to motion 1st equation vf=vi+ at
vi=0
therefore ,
vf=at
sqr(253)=2.3t
t=sqr(253)/2.3
=6.9 sec.

or, to get the time according to motion 2nd equation
d=vit+1/2 at^2
vi=0
d=1/2at^2
55=1/2×2.3t^2
t^2=47.8
t=sqr(47.8)
t=6.9sec.

The answer is b hope this