A magnetic field of magnitude 0.360 T is oriented perpendicular to the plane of a circular loop. HINT (a) Calculate the loop radius (in m) if the magnetic flux through the loop is 2.65 Wb. m (b) Calculate the new magnetic flux (in Wb) if the loop radius is doubled.

(a)  the loop radius (in m) = 1.531 m

(b) the new magnetic flux, when the loop radius is doubled = 10.61 Wb

Explanation:

Given;

magnitude of magnetic field, B = 0.36 T

magnetic flux, Ф = 2.65 Wb

(a)  the loop radius (in m)

magnetic flux is given by;

Ф = BA

Where;

A is the circular area of the loop

A = πr²

Ф = B.πr²

(b) the new magnetic flux, when the loop radius is doubled

Ф = B.πr²

Ф = 0.36 x π x (2 x 1.531)²

Ф = 10.61 Wb

note: the given question is incomplete.

complete question is given below.

which is an example of kinetic energy?

a. the energy stored in ethanol  

b. a hockey puck sliding across the ice  

c. a compressed spring  

d. a ball sitting at the top of a ramp

solution: the kinetic energy is the energy posses by the virtue of the motion of the object.

in the given options, a, c and d are the example of potential energy because it is the energy posses by the virtue of the rest of the object. but option b has the kinetic energy as the object is in motion.

hence, a hockey puck sliding across the ice   is the apex example of kinetic energy.

so, the option (b) a hockey puck sliding across the ice   is the correct option.