A spherical balloon is inflating with helium at a rate of 192pi ft^3/min. How fast is the balloon's radius increasing at the instant the radius is ft?

3ft/min

Explanation:

Complete question:

A spherical balloon is inflating with helium at a rate of 192pi ft^3/min. How fast is the balloon's radius increasing at the instant the radius is 4ft?

Volume of a sphere = where:

r is the radius of the sphere:

Using the chain rule to find dV/dt we have:

is the rate at which the balloon's radius is increasing

is the rate at which the volume is increasing

Given

radius = 4ft

Required

From the formula:

Get

Hence the balloon radius is increasing at the rate of 3ft/min.

moving ball hits still ball. mover stops, hit ball moves. momentum transfer.

i think it's 35 meters