It took a squirrel 0.50\,\text s0.50s0, point, 50, start text, s, end text to run 5.0\,\text m5.0m5, point, 0, start text, m, end text leftward to a nearby tree while maintaining a constant acceleration. The squirrel was running 15\,\dfrac{\text m}{\text s}15 s
m

15, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction leftward when it reached the tree.
What was the squirrel's initial velocity?

The answer is as follows in the photo

stands for electromotive force and it is measured in volts. despite its name, it is not actually the force in the sense of being a "pushing" or "pulling" (not measured in newtons).an equation that relates emf,  ℰ,  to a battery's terminal voltage, v, current, i, and internal resistance, r, is    ℰ = v + irin this case, the emf can be interpreted as a voltage—a difference in electric potential.i would not say that it would be considered an energy. if emf can be defined as the energy/work per a unit charge from a battery or other electric source, then it is not strictly energy.