10.0 mF parallel-plate capacitor with circular plates is connected to a 12.0 V battery. (a) What is the charge on each plate

0.12 C.

Explanation:

The following data were obtained from the question:

Capacitor (C) = 10 mF

Potential difference (V) = 12 V

Charge (Q) =?

Next, we shall convert 10 mF to farad (F). This can be obtained as follow:

1 mF = 1×10¯³ F

Therefore,

10 mF = 10 mF × 1×10¯³ F/ 1mF

10 mF = 0.01 F

Therefore, 10 mF is equivalent to 0.01 F.

Finally, we shall determine the charge on the capacitor as illustrated below:

Capacitor (C) = 0.01 F

Potential difference (V) = 12 V

Charge (Q) =?

Q = CV

Q = 0.01 × 12

Q = 0.12 C

Therefore, the charge on the capacitor is 0.12 C.

answer///terminator or twilight zone;

the answer is the first electromagnet (a). this is because it has more coils around the ferromagnetic material. increasing the number of coils increases the surface area in which the metal interacts with the current in the coil. this enables more atoms in the metal to become aligned hence becoming more magnetized.