A 60-kg skier pushes off the top of a frictionless hill with an initial speed of 4.0 m/s. How fast will she be moving after dropping 10 m in elevation

Explanation:

To know how fast will she be moving after dropping 10m in elevation, we will use the equation of motion

v² = u²+2gS

S is the elevation

g is the acceleration due to gravity

v is the final velocity

u is the initial velocity

Substitute the given values

v² = 4²+2(9.81)(10)

v² = 16+(19.62)(10)

v² = 16+196.2

v² = 212.2

v = √212.2

v = 14.57m/s

Hence she will be moving at 14.57m/s

think its the third option